if A is acute angle and tan =5/12 find the value of cosec A
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Let height=p
hypotenuse=h
base=b
tanA=5/12
tanA=p/b
p/b=5/12
=5x/12x
so: p=5x, b=12x
By Pythagoras theorem:
h²=(5x)²+(12x)²
=h²=25x²+144x²
=169x²
h=13x
cosecA=h/p
=13x/5x
=13/5
Answer:- 13/5
Hope it helps:-)
Anonymous:
height=p?? or perpendicular =p huh
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