Question

if A is an acute angle and tanA =3/4,find the value of 5cosecA+10secA​

Answer 1

Answer:

Given, sinA=3/5 and A is an acute angle

So, in ΔABC we have ∠B=90

And AC=5 and BC=3

By Pythagoras theorem,

AB= root (Ac^2-b^2)

root(5^2-3^2)

root 16

=4

Now,

cosA=AB/AC=4/5

tanA=BC/AB=3/4

cotA=1/tanθ=4/3.

secA=1/cosθ=5/4.

cosecA = 1/sinθ=5/3.

Answer 2

Answer:

20.83

Step-by-step explanation:

By Pythagoras theorem, and using the triangle,

Cosec A= Hypotenuse/ opposite side

= 5/3

Sec A = Hypotenuse / Adjacent side

= 5/4

So, 5cosecA + 10 secA = 5×(5/3) + 10×(5/4)

= 25/3 + 50/4 = 25/3 + 25/2 = 125/6 = 20.83