Question

if a is equal to 7 minus 4 root 3 find the value of root a + 1 upon root a

Answer 1

hiii!!!

here's ur answer...

given :- $a= 7-4 \sqrt{3}$

therefore a + 1 upon root a =
 
$\frac{(7-4 \sqrt{3})+ 1 }{7-4 \sqrt{3} } * \frac{7+4 \sqrt{3} }{7+4 \sqrt{3} } \\ \\ = \frac{(8-4 \sqrt{3})(7+4 \sqrt{3} ) }{(7-4 \sqrt{3} )(7+4 \sqrt{3}) } \\ \\ = \frac{8(7+4 \sqrt{3})-4 \sqrt{3} (7+4 \sqrt{3} ) }{ 7^{2} - (4 \sqrt{3} )^{2} } \\ \\ = \frac{56+32 \sqrt{3} -28 \sqrt{3}-(16*3) }{49-(16*3)} \\ \\ = \frac{56-48+4 \sqrt{3} }{49-48} \\ \\ = 8+4 \sqrt{3}$

hope this helps..!!

Answer 2

The answer is 4.


Hope this helps!