if a is equal to a + b + C is equal to 12 a square + b square + c square is equal to 90 find the value of a cube plus b cube plus c cube minus 3 ABC
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Answer:
Value of a³ + b³ + c³ - 3abc is 756.
Step-by-step explanation:
Given:
a + b + c = 12
a² + b² + c² = 90
To find: a³ + b³ + c³ - 3abc
We use the identity,
( a + b + c )² = a² + b² + c² + 2ab + 2cb + 2ac
( 12 )² = 90 + 2ab + 2cb + 2ac
2 (ab + cb + ac) = 144-90
ab + cb + ac = 54/2
ab + cb + ac = 27
Now using identity,
a³ + b³ + c³ - 3abc = ( a + b + c)( a² + b² + c² - ab - cb - ac )
= ( 12 ) ( 90 - (ab + cb + ac))
= ( 12 ) ( 90 - (27))
= ( 12 ) ( 63 )
= 756
Therefore, Value of a³ + b³ + c³ - 3abc is 756.
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