If A is non singular matrix then prove that A-¹=AdjA/|A|
Answers
Answered by
1
Answer:
I suggest that you write these equations on paper incase you find them clumsy.
It is easy to see that |kA| = (k^n)|A| where k is a constant and n is the order of the square matrix A.We know that |A^-1| is 1/|A|.Since A^-1 is (1/|A|) adj (A),we get |A^-1| = (1/|A|)^n |adj(A)| which implies |A|^(n)/|A| is |adj(A)|.
So |A|^(n-1) = |adj(A)|.
QED
Similar questions