if a is rational number and √b is irrational then prove that (a+√b) is irrational
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Step-by-step explanation: prove by contrary
assume a+√b be rational
so a+√b=r÷s whe r and s are integers
a+√b=r/s
√b=r/s-a
√b=r-as/s
√b here proves to be a rational number by taking r-as as p and s=q because p/q is a rational number. but √b is irrational number. so our assumption is wrong, so a+√b is an irrational number.
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