Question

if a is rupees 1000 is invested annual rate of interest of 10% amounts after 2 years if compunding is done annualy is​

Answer 1

Answer:

Amount = ₹1210

Step-by-step explanation:

$a = p \: (1 + \frac{r}{100})^{n}$

A = 1000 ( 1 + $\large{\frac{10}{100}}$ )²

A = 1000 ( $\large{\frac{11}{10}}$ )²

A = $1000 × \large{\frac{11}{10} × \frac{11}{10}}$

$\large{\boxed{ A = 1210}}$

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Mark Brainliest, if it helps.