If a is the A.M. between b and c, b be the G.M. between a and c, then show that 1/a,1/b,1/c are in A.P.
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Answer:
something is wrong, if b is the A.M between a and c then will be right.
Step-by-step explanation:
Given,
b is A.M between a and c , then
a+c = 2b
again,
b is G.M between a and c , then
ac = b²
Now,
On dividing the two by each other,
(a+c)/ac = 2b/b²
1/c + 1/a = 2/b
1/a + 1/c = 2/b
so,
1/a , 1/b and 1/c are in A.P
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