Math, asked by mass5619, 14 hours ago

If a is the A.M. between b and c, b be the G.M. between a and c, then show that 1/a,1/b,1/c are in A.P.

Answers

Answered by vikkiain
0

Answer:

something is wrong, if b is the A.M between a and c then will be right.

Step-by-step explanation:

Given,

b is A.M between a and c , then

a+c = 2b

again,

b is G.M between a and c , then

ac =

Now,

On dividing the two by each other,

(a+c)/ac = 2b/

1/c + 1/a = 2/b

1/a + 1/c = 2/b

so,

1/a , 1/b and 1/c are in A.P

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