If a is thrice as fast as b and together can do a work in 21 days. in how many days a alone can do the work?
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Answered by
3
If B can do x amount of work in 21 days then A can 3x amount of work in 21 days.
Solve for x: A + B = 21 days therefore 3x + x = 21 days
4x = 21 days
x = 21/4 days
x = 5 1/4 days
If B is not there then A has to do their work and B's work therefore it will take A 21 days + 5 1/4 days = 26 1/4 days
Answered by
2
Answer:
28 days
Step-by-step explanation:
let 'x' be the number of days worked by 'A'
A = 3x
B = x
=>1/3x + 1/x = 1/21
=>4/3x = 1/21
=>3x = 21*4
=>x = (21*4)/3
=>x = 7*4
=>x = 28
Hence, 'A' can do the same work alone in 28 days.
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