If a ladder 10 m long reaches a window 8 m above the ground, then find the distance of the foot of the ladder from the base of the wall.
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Construct a a right angle ABC in which Angle b is 90 degree.
Ac=ladder=10m
AB=wall=8m
By,Pythagoras theorem
AC²=BC²+AB²
100=BC²+64
√36=BC
BC=distance between foot of ladder and base of wall =6m
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