If a leap year is selected at random .Find the probability of 53 tuesday.
Wrong answer will be reported
Answers
Answered by
1
2) In Leap Year,
There are 366 days,
366 days = 52 weeks + 2days
These 2 days can be
{ MT , TW , WTh , ThF, FSa , SaS , SM}
n(S) = 7
Event , E: Getting Tuesday
n(E) = 2
Hence P(E) = n(E)/n(S) = 2/7
Answered by
0
Hey there!
No. of days in leap year = 366 days
= 52 weeks and 2 days
These two days can be:
S = { MT , TW , WTh , ThF, FSa , SaS , SM}
Total outcomes = 7
n(getting thusday) = 2
Probability = n(getting thursday) / total outcomes
= 2 / 7
Similar questions