Math, asked by akshit200599, 10 months ago

If a leap year is selected at random .Find the probability of 53 tuesday.

Wrong answer will be reported​

Answers

Answered by ShruthiS
1

2) In Leap Year,

There are 366 days,

366 days = 52 weeks + 2days

These 2 days can be

{ MT , TW , WTh , ThF, FSa , SaS , SM}

n(S) = 7

Event , E: Getting Tuesday

n(E) = 2

Hence P(E) = n(E)/n(S) = 2/7

Answered by duragpalsingh
0

Hey there!

No. of days in leap year = 366 days

                                        = 52 weeks and 2 days

These two days can be:

S = { MT , TW , WTh , ThF, FSa , SaS , SM}

Total outcomes = 7

n(getting thusday) = 2

Probability = n(getting thursday) / total outcomes

                  = 2 / 7

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