Question

If a length of a rectangle is 7 more than it's breadth and it's perimeter is 30m then find its length and breadth.

Answer 1

Answer:

$\large{\boxed{\sf \star\: Length = 11 \: m}}$

$\large{\boxed{\sf \star\: Breadth = 4 \: m}}$

Step-by-step explanation:

Let the breadth of the rectangle be x and it's Length = ( x + 7 ) m.

We know that-

Perimeter of rectangle = 2 ( l + b )

⇒ 2( x + 7 + x) = 30

⇒ 2x + 7 = 30/2

⇒ 2x + 7 = 15

⇒ 2x = 15 - 7

⇒ 2x = 8

⇒ x = 8/2

⇒ x = 4

Therefore, the dimensions of rectangle are:

Length = x + 7 = 4 + 7 = 11 m

Breadth = x = 4 m

Hence, the length of the rectangle is 11m and breadth is 4m.

Answer 2

Answer :-

Let the breadth of rectangle = x

Length = x + 7

Given :-

Perimeter of rectangle = 30 m

To Find :-

Length and breadth.

Solution :-

Perimeter of rectangle = 30

$\implies$2 (l + b) = 30

$\implies$2 (x + 7 + x) = 30

$\implies$2 (2x + 7) = 30

$\implies$4x + 14 = 30

$\implies$4x = 30 - 14

$\implies$4x = 16

$\implies$x = 16/4

$\implies$x = 4

So, the Breadth is 4 m ;

So, the Breadth is 4 m ;Length = 4 + 7 = 11 m.

$\boxed{\star{Length = 11 m}}$

$\boxed{\star{Breadth = 4 m}}$