If a length of a wire is l and resistivity is rho and radius of wire is 10 cm what will be the new resistance
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Answer:
Hence, the new resistance of the wire = 7pl / 2200 ohms
Explanation:
We know that,
When the wire of length 'l' with a area of cross section 'A' and specific resistivity 'rho - p', then the resistance 'R' of the wire :
R = (p × l) / A
Here its is given,
Radius of wire = 10 cm
Area = πr^2 = 22/7 × 10 × 10 = 2200/7 cm^2
Resistivity = rho (p)
Length = l
Then,
Resistance, R :
R = (p × l) / (2200/7) = 7pl / 2200 ohms
Hence, the new resistance of the wire = 7pl / 2200 ohms
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