Question

Q5. If polynomial x4 + x3 + 6x2 + ax + b is exactly divisible by another polynomial
x2 + 1, find the value of a and b.​

Answer 1

Answer:

a=1 and b=5

Step-by-step explanation: $\sqrt[x^2+1]{x^4+x^3+6x^2+ax+b} \\remainder=0=ax-x+b-5 \\so a=1 and b=5 \\hope it helps :))$