if a light of wavelength 4000 A 2 points
is incident on the metal
surface of work function 5 eV
will the electron be ejected or
not. *
Answers
Answered by
0
Answer:
no
Explanation:
Energy of incident light must be >or=work function of metal
12400/4000=3.1eV which is less than 5eV
so electrons will not be ejected
please mark my answer as brainliest
Answered by
4
ANSWER
we know
- light ray is a bundle of photon
- energy of incident photon = hc/lamda
- but as here work function is given in ev
..for calculation of energy of incident photon
in electeon volt formula is
= 12400/lamda where lamda is in angstrom
apply this
energy of photon E = 12400 /4000
= 3.1 ev
here given that work function is 5 ev . for electron to be released photon energy must greater then work function
for example :- a book apply force of 10 newton on a table. for move that book you also have to apply force of 10 newton .
so result is electeon not to be ejected
follow me
bye
Similar questions