If a line AB parallel to line DE find angle ACD
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I will be denoting an angle just by three letters.
In the figure,
BAC and CED are alternate angles.
So, BAC = CED = 35°
For ACD, the two interior opposite angles are CED and CDE.
As exterior angle = sum of interior opposite angles,
ACD = CDE + CED
= 53° + 35°
So, ACD = 88°
Thus measure of angle ACD is 88°
In the figure,
BAC and CED are alternate angles.
So, BAC = CED = 35°
For ACD, the two interior opposite angles are CED and CDE.
As exterior angle = sum of interior opposite angles,
ACD = CDE + CED
= 53° + 35°
So, ACD = 88°
Thus measure of angle ACD is 88°
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