if a llgm and triangle are on asme base and between same parallels. prove that area of triangle is equal to half area of llgm
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area of llgm is area of ∆ CAD+∆BAD.
1/2×AB×CO+1/2×AD×OB.
area of ∆ CAD is 1/2×AB×CO so,
llgm equal to 2(CAD).
1/2×AB×CO+1/2×AD×OB.
area of ∆ CAD is 1/2×AB×CO so,
llgm equal to 2(CAD).
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