Question

If a = log2/3, b = log3/5 and c = 2log √3/5 , find the vale of a + b + c

Answer 1

$heya \\ formulas \\ \\ log(m \div n) = log(m) - log(n) \\ \\ log(x {}^{n} ) = n log(x) \\ \\ \\ \\ a = log(2) - log(3) \\ \\ b = log(3 ) - log(5) \\ \\ c = 1 \div 2 log(3) - log(5) \\ \\ adding \: both \: the \: 3 \: equations \\ \\ a + b + c = log(2) - 2 log(5) + 1 \div 2 log(3) \\ \\ \\ \\ hv \: a \: nyc \: tym$