Question

If a = log2412, b = 2436 and c = log4836, then find the value of

1 + abc

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Answer 1

Solution :

1 + abc = 1 + log2412 ⋅ log3624 ⋅ log4836

1 + abc = 1 + log3612 ⋅ log4836

1 + abc = 1 + log4812

1 + abc = log4848 + log4812

1 + abc = log48(48 ⋅ 12)

1 + abc = log48(2 ⋅ 12)2

1 + abc = 2log4824

1 + abc = 2log3624 ⋅ log4836

1 + abc = 2bc