If a = log503 and c = log 5 , then the value of log2012 in terms of a and c is
shreysaxena:
Answer pleaaase
Answers
Answered by
13
The answer is given below :
RULE :
1. log a = b
=> a = e^b
2. log (ab)
= log a + log b
3. log (e^a) = a
SOLUTION :
Given that,
a = log 503
and
b = log 5
=> log 5 = b
=> 5 = e^b
=> 4 × 5 = 4 × e^c, multiplying both sides by 4
=> 4 = 4/5 × e^c
Taking log to both sides, we get
log 4 = log (4/5 × e^c)
=> log 4 = log (4/5) + log (e^c)
=> log 4 = log (4/5) + c
Now, log 2012
= log (503 × 4)
= log 503 + log 4
= a + log (4/5) + c
= a + c + log (4/5),
which is the required value of log (2012) in termss of a and c.
Thank you for your question.
RULE :
1. log a = b
=> a = e^b
2. log (ab)
= log a + log b
3. log (e^a) = a
SOLUTION :
Given that,
a = log 503
and
b = log 5
=> log 5 = b
=> 5 = e^b
=> 4 × 5 = 4 × e^c, multiplying both sides by 4
=> 4 = 4/5 × e^c
Taking log to both sides, we get
log 4 = log (4/5 × e^c)
=> log 4 = log (4/5) + log (e^c)
=> log 4 = log (4/5) + c
Now, log 2012
= log (503 × 4)
= log 503 + log 4
= a + log (4/5) + c
= a + c + log (4/5),
which is the required value of log (2012) in termss of a and c.
Thank you for your question.
Answered by
21
HELLO DEAR,
we know that:-
1. log a = b
⇒ a = e^b
(2). log (ab)
⇒log a + log b
AND,
log (e^a) = a
Now,
Given that,
a = log 503
and
b = log 5
⇒ log 5 = b
⇒ 5 = e^b
⇒4 × 5 = 4 × e^c,
∴ [ multiply both sides by 4 ]
⇒ 4 = 4/5 × e^c
∴ [ Taking log to both sides ]
we get,
log 4 = log (4/5 × e^c)
⇒ log 4 = log (4/5) + log (e^c)
⇒ log 4 = log (4/5) + c
Now,
log 2012
⇒log (503 × 4)
⇒ log 503 + log 4
⇒ a + log (4/5) + c
= a + c + log (4/5),
HENCE,
the value of log (2012) in termss of a and c
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:-
1. log a = b
⇒ a = e^b
(2). log (ab)
⇒log a + log b
AND,
log (e^a) = a
Now,
Given that,
a = log 503
and
b = log 5
⇒ log 5 = b
⇒ 5 = e^b
⇒4 × 5 = 4 × e^c,
∴ [ multiply both sides by 4 ]
⇒ 4 = 4/5 × e^c
∴ [ Taking log to both sides ]
we get,
log 4 = log (4/5 × e^c)
⇒ log 4 = log (4/5) + log (e^c)
⇒ log 4 = log (4/5) + c
Now,
log 2012
⇒log (503 × 4)
⇒ log 503 + log 4
⇒ a + log (4/5) + c
= a + c + log (4/5),
HENCE,
the value of log (2012) in termss of a and c
I HOPE ITS HELP YOU DEAR,
THANKS
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