if a man has provisions in his house for 36 days for 4 persons,how long will the food last if he is joined by 14 guests
Answers
Answered by
1
No. of days for which 4 persons will have food = 36
No. of days for which 1 person will have food = 36/4 = 9
If 14 more guests are joined then,
Total No. of guests = 4 + 14 = 18
So,
No. of days for which 18 persons will have food = 9 x 18 = 162
Hence, the food will last for 162 days if the person is joined by 14 more guests.
No. of days for which 1 person will have food = 36/4 = 9
If 14 more guests are joined then,
Total No. of guests = 4 + 14 = 18
So,
No. of days for which 18 persons will have food = 9 x 18 = 162
Hence, the food will last for 162 days if the person is joined by 14 more guests.
Golda:
wrong answer. If the persons are increasing then how the same quantity of food will last for so many days (You have mentioned 162 days).
Answered by
2
Solution :-
More persons, the food will last for less days.
So, this is a case of inverse variation.
Persons Days
4 36
4 + 14 = 18 x
By inverse variation.
⇒ 18x = 36*4
⇒ x = 144/18
⇒ x = 8
So, the food will last for 8 days if he is joined by 14 guests.
Answer.
More persons, the food will last for less days.
So, this is a case of inverse variation.
Persons Days
4 36
4 + 14 = 18 x
By inverse variation.
⇒ 18x = 36*4
⇒ x = 144/18
⇒ x = 8
So, the food will last for 8 days if he is joined by 14 guests.
Answer.
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