Question

if a man travels at a speed of 30km/hr, he reaches his destination 10min. late and if he travels at a speed of 42km/ hr, he reaches destination 10min. early. the distance travelled is

Answer 1

35 km as

Let the distance be x km.

Then, correct time at a speed of

30 km / h = x30 - 1060

Correct time at a speed of 42 km /h

= x42 + 1060

=> x30 - 1060 = x42 + 1060

=> x30 - x42 = 26

=> x(12)1260 = 26

=> 72 x = 1260 × 2

=> x = 1260×272 => x = 35 km

Answer 2

Answer:

The distance traveled = 35 km

Step-by-step explanation:

The speed of the man$S=30\text{ km/hr}$

Consider the distance traveled = x km

therefore, Time taken to reach his destination = $T_{1}=\frac{x}{30}\text{ hr}$

If the speed of the man$S=42\text{ km/hr}$

therefore, Time taken to reach his destination = $T_{2}=\frac{x}{42}\text{ hr}$

Total difference between time = 20 min =$\frac{20}{60}=\frac{1}{3}$ hr

Therefore,

$T_{1}-T{2}=\frac{1}{3}\\\\\Rightarrow\frac{x}{30}-\frac{x}{42}=\frac{1}{3}\\\\\Rightarrow \frac{x}{10}-\frac{x}{14}=1\\\\\Rightarrow\frac{7x-5x}{70}=1\\\\\Rightarrow 2x=70\\\\\Rightarrow x=35$

The distance traveled = 35 km