if a man travels at at a speed of 30km/hr ,he reaches his destination 10 minutes late and if he travels at a speed of 42km/hr ,he reaches his destination 10 minutes early, the distance travelled is
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Answer: The distance travelled is 35km.
Step-by-step explanation:
Distance = D ( Let)
Speed = 30km/hr
On increasing his speed to 42km/hr, he reached faster
In the first case, he was 10 minutes late and in the second case, he was 10 minutes early and so the difference between the two times is 20 minutes.
As we know: Time = Distance/Speed
First case, T1 = D/30 hours
Second case, T2 = D/42 hours
So, forming an equation:
T1-T2 = 20/60 hours = 1/3 hours
Therefore, D/30 - D/42 = 1/3
Solving this equation, we get D as 35 km.
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