Question

If a mole is defined to be 3 x 10^24 (instead of Avogadro's Number, 6x10^23), what would be
the mass of one mole of Argon atoms? (Atomic mass of Ar on conventional scale is 40)
(A) 40 gm
(B) 200 gm
(C)20 g
(D) 8 gm​

Answer 1

Argon contains 6.023×10^23 units

its atomic mass on conventional scale is 40

So, The atomic mass

if mole is 3×10^24 is

3×10^24×40/ 6×10^23 = 200.

The answer is 200 grams.

Answer 2

Answer:

The mass of one mole of Argon atom will be 200g.

Explanation:

We know that one mole of an atom contains 6×10^23 atoms.

The atomic mass of Argon is 40g.

Therefore, 6×10^23 atoms of Ar = 40g

It is given that a mole is defined to be 3×10^24 atoms.

We have to find the mass of one mole of Argon atoms when the Avogadro's number is changed.

Let the mass be x.

6×10^23 atoms of Ar weigh 40g

3×10^24 atoms of Ar weigh x g

Therefore,

x = $\frac{40*3*10^{24}}{6*10^{23}}$

x = $\frac{120*10^{24}}{6*10^{23}}$

x = 20×10

x = 200g

Therefore, the mass of one mole of Argon atom will be 200g.

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