Question

if a momentum of a body is decreased by 10% then what is the percentage inccrease kinetic energy

Answer 1

It will be increased by 0.19%
Let the initial mass of the body be m and its velocity be v. 
Initial momentum of the body = mv 
Initial KE = mv^2/2 
If the momentum decreases by 10%, new momentum = mv - 10% of mv 
= mv - 10/100mv 
= mv - mv/10 
=9mv/10 
=m(9v/10) 
New velocity = 9v/10 
Increase in velocity = v/10 
New KE = m(9v/10)^2/2 
= 81/100mv^2/2 
Increase in KE = 0.19%

Answer 2

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