Question

If a net horizontal force of 130 N is applied to a person with mass 60 kg who is resting on the edge of a swimming pool, what is the horizontal acceleration produced?

Answer 1

Hi_____-–
According to me,
Force =130 N
m = 60 kg
Force applied = mass of the person × horizontal acceleration
130 = 60 × a
a = 13/6 =2.16 m/(s^2) (approx.)

Answer 2

Given:

• Horizontal force applied on man = 130 N.
• Mass of man = 60 kg.

To find:

Acceleration of the man ?

Calculation:

• Force is defined as a vector quantity represented by the product of mass and acceleration.

$Force = mass \times acceleration$

$\implies \: F = m \times a$

$\implies \: a = \dfrac{F}{m}$

$\implies \: a = \dfrac{130}{60}$

$\implies \: a \approx \: 2.167 \: m {s}^{ - 2}$

So, acceleration of man is approximately 2.167 m/s².