if a number 573 xy is divisible by 9 then what is the value of x + Y
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If 573xy is divisible by 90, then y = 0. So we have 573x0.
For any number to be divisible by 9, the sum of the digits should be 9. Here we have 5+7+3 = 15, 1+5 = 6.
Therefore, x should be 9–6 = 3.
So the actual number is 57330.
The sum of x+y = 3.
For any number to be divisible by 9, the sum of the digits should be 9. Here we have 5+7+3 = 15, 1+5 = 6.
Therefore, x should be 9–6 = 3.
So the actual number is 57330.
The sum of x+y = 3.
Answered by
1
Since 630 is the only number divisible by 90, in the set of three digit numbers starting with 6 . Since the number is divisible by 90, the last step gives,
6xy - 630 = 0
6xy = 630
Therefore x = 3, y = 0
So x + y = 3.
6xy - 630 = 0
6xy = 630
Therefore x = 3, y = 0
So x + y = 3.
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