Question

if a number from 1-15 is chosen at random, find the probability of choosing
1 a prime number
2 an even number
3 a number divisible by 5
4 a number divisible by 2 and 5 both

Answer 1

Total numbers = 15

1. Total Prime numbers = 6 (2,3,5,7,11,13)

So, P(E1) = 6/15 = 2/5...●

2. Total Even numbers = 7 (2,4,6,8,10,12,14)

So, P(E2) = 7/15...●

3. Total numbers which are divisible by 5 = 3 (5,10,15)

So, P(E3) = 3/15 = 1/5..●

4. Total numbers which are divisible by 2 and 5 = 1 (10)

So, P(E4) = 1/15...●

●●●●●●●●●●●●●●●●●

Hope it was helpful.

Answer 2

PRIME NUMBERS = 1,3,5,7,11,13
NO. OF PRIME NUMBERS = 6
TOTAL NO. = 15
PROBABILITY = 6/15 = 2/5

EVEN NUMBERS =2,4,6,8,10,12,14
NO. OF EVEN NUMBERS = 7
TOTAL NO. = 15
PROBABILITY = 7/15

NO. DIVISIBLE BY 5 =5,10,15
NO. OF NUMBERS = 3
TOTAL NO. = 15
PROBABILITY = 3/15 = 1/5

NO. DIVISIBLE BY 2 AND 5 = 2,4,5,6,8,10,12,14,15
NO. OF NUMBERS = 9
TOTAL NO. = 15
PROBABILITY =9/15 = 3/5

MARK AS BRAINLIST