Question

If a number is chosen at random from the set {1,2,3..., 100}, then the probability that the chosen number is a perfect cube is

Answer 1

Answer:

Probability that the chosen number is a perfect cube is $\frac{1}{25}$                  

Step-by-step explanation:

Given : If a number is chosen at random from the set {1,2,3..., 100}.

To find : The probability that the chosen number is a perfect cube?

Solution :

Total number of outcome is  set {1,2,3..., 100} = 100

Number having a perfect cube are

$1^3=1$

$2^3=8$

$3^3=27$

$4^3=64$

Favorable outcome of chosen number is a perfect cube = 4

So, Probability that the chosen number is a perfect cube is

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{4}{100}$

$\text{Probability}=\frac{1}{25}$

Therefore, Probability that the chosen number is a perfect cube is $\frac{1}{25}$

Answer 2

Answer:

The probability that the chosen number exists in a perfect cube is $\frac{1}{25}$.

Step-by-step explanation:

Given:

If a number exists chosen at random from the set $\{1,2,3 \ldots, 100\}$.

To find:

The probability that the chosen number exists a perfect cube.

Step 1

The total number of outcomes exists set $\{1,2,3 \ldots, 100\}=100$

Number having a perfect cube is

$&1^{3}=1$

$&2^{3}=8$

$&3^{3}=27$

$&4^{3}=64$

The favorable outcome of chosen number is a perfect cube $=4$.

Step 2

So, the Probability that the chosen number is a perfect cube is

Probability $=\frac{\text { Favorable outcome }}{\text { Total outcome }}$

Probability $=\frac{4}{100}$

Probability $=\frac{1}{25}$

Therefore, the probability that the chosen number is a perfect cube exists $\frac{1}{25}$.

#SPJ2