Math, asked by AkshatNasa1717, 1 year ago

If a square b square c square are in ap prove that a by b + c b by c + a c by a + b are in ap

Answers

Answered by humanoid1264
4

We know, 2 × middle term = sum of remaining two.

So,

➡ 2 × b = a + c

➡ 2b = a + c -------: ( 1 )

If b + c , c + a , a + b are also in A.P.

2 × ( c + a ) = b + a + b + c is true

Or, 2 × ( c + a ) = c + a + b + b is true

Or, 2 × ( c + a ) = c + a + 2b is true

Or, 2 × ( 2b ) = 2b + 2b is true

Or, 4b = 4b is true

0 = 0

Hence, both are equal. It means that b + c , c + a , a + b are in A.P.

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