Question

If a number is divided by another number then quotient is 2 and remainder is 2. If five times the second number is divided by first number then quotient is 2 and remainder is 3 then find the numbers. with explanation

Answer 1

Answer:

A = 16 and B = 7

Step-by-step explanation:

Let the first number be A and second number be B

Now, if you observe Division carefully we can see that

Dividend = (Divisor × Quotient) + Remainder

For example, let's divide 5 by 2

where 5 is the Dividend and 2 is the Divisor

_2___

2 | 5

-4

_____

1

———–

Here, Dividend = 5, Divisor = 2, Quotient = 2 and Remainder = 1

If we check,

5 = (2 × 2) + 1

So, it is valid

Now, let us come back to our Question

According to the Question,

A = 2×B + 2

A = 2B + 2 ------- 1

also,

5B = 2×A + 3

5B = 2A + 3 ------- 2

So, we get two equations,

A = 2B + 2 and 5B = 2A + 3

Now, from eq.1 we get A, substituting that in eq.2 we get

5B = 2A + 3

5B = 2(2B + 2) + 3

5B = 4B + 4 + 3

5B - 4B = 7

so, B = 7

Now we can find A using eq.1,

A = 2(7) + 2

A = 14 + 2 = 16

So, A = 16 and B = 7

You can also check this result it will be true

Hope it helped and you understood it........All the best