Question

if a number x is chosen at random from the numbers -2,-1,0,1,2, what is the probability that x2 < 2?

Answer 1

Okay lets check,

(-2)^2 = 2 which is = 2
(-1)^2 = 1 and 1<2
0^2 = 0. 0<2
1^2 = 1 1<2
2^2=4. 4>2

So the favourable outcomes are only -1,0,1
So probability will be 3/5

Answer 2

Answer:

The probability of the inequality is 3/5

Step-by-step explanation:

Given :

we are given some number

-2 , -1 , 0 , 1 , 2

To Find :

The probability of randomly selecting a number being $x^2 < 2$

Solution :'

Since given numbers are = -2 , -1 , 0 , 1 , 2

Total numbers are = 5

Since we have to find the probability of $x^2 < 2$

squares of given numbers are = 4 , 1 , 0 , 1 , 4

Here the numbers that satisfies the given inequality are -1 , 0 , 1

here total number of results that satisfies the given inequality = 3

Then the probability  = $\frac{\text{Number of favourable cases}}{\text{Number of Total cases}}$

Here number of Favourable cases = 3

Total number of cases = 5

So the probability = $\frac{3}{5}$

Hence we have calculated that the probability of the inequality is 3/5

#SPJ3