if a number x is chosen at random from the numbers -2,-1,0,1,2, what is the probability that x2 < 2?
Answers
Answered by
105
Okay lets check,
(-2)^2 = 2 which is = 2
(-1)^2 = 1 and 1<2
0^2 = 0. 0<2
1^2 = 1 1<2
2^2=4. 4>2
So the favourable outcomes are only -1,0,1
So probability will be 3/5
(-2)^2 = 2 which is = 2
(-1)^2 = 1 and 1<2
0^2 = 0. 0<2
1^2 = 1 1<2
2^2=4. 4>2
So the favourable outcomes are only -1,0,1
So probability will be 3/5
Answered by
0
Answer:
The probability of the inequality is 3/5
Step-by-step explanation:
Given :
we are given some number
-2 , -1 , 0 , 1 , 2
To Find :
The probability of randomly selecting a number being
Solution :'
Since given numbers are = -2 , -1 , 0 , 1 , 2
Total numbers are = 5
Since we have to find the probability of
squares of given numbers are = 4 , 1 , 0 , 1 , 4
Here the numbers that satisfies the given inequality are -1 , 0 , 1
here total number of results that satisfies the given inequality = 3
Then the probability =
Here number of Favourable cases = 3
Total number of cases = 5
So the probability =
Hence we have calculated that the probability of the inequality is 3/5
#SPJ3
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