CBSE BOARD X, asked by Developero, 1 year ago

If a object is moving away from a convex lens. What is the in intensity in the screen.....

Answers

Answered by Singhsuhani
2
the size of the image decreases.
Because convex lens is a converging lens so the more distant rays come the more they converge to form a diminished converged img.
However there comes a time when screen cannot get that diminished image too and image is not visible.
Thus distant object rays are focussed but they are so diminished that there intensity which is increased due to convergence is not visible .

Singhsuhani: hope it would help. Intensity increases but visibility decreases
Answered by Anonymous
6
☆Heya your answer is here☆

Moving the object further from the lens gives the following ray diagram.As you can see, moving the object further from the lens causes the image to move closer to the lens and become smaller. If we move the object further and further away, the image will get smaller and smaller. The image's location will move closer and closer to the focal point. If the object were very very far away, like the sun, then the light would be focused to a point - the focal point.Moving the object closer to the lens gives the following ray diagram.Clearly, moving the object closer to the lens makes the image become both larger and further away. As you move the object closer and closer to the focal point, the image will become further and further away.Let us try moving the object still closer to the lens. (We will have to make the object smaller in height so that we can get the image on the screen.)As expected the image moves further away and becomes much bigger than the object.We know from before that if the object were right at the focal point, the rays would come out horizontally and the image would be in some sense infinitely far a
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