Question

if a packet is projected upwards with velocity u from a height h or released from a balloon ascending with a velocity u and t is the time taken for the packet to reach the ground then the equation formed will be :- _________________________​

Answer 1

Answer: Given, u=12 ms−1

s=−65 m

⇒g=−10 ms−2

We know that, s=ut+21gt2

⇒−65=12t−21×10t2

−65=12t−5t2

⇒5t2−12t−65=0

5t2−25t+13t−65=0

5t(t−5)+13(t−5)=0

(5t+13)(t−5)=0

⇒t=−513s or t=5s.