if a pair of linear equations is given by a1x+b1y+c1= 0 and a2x+b2y+c2=0 the equations of these lines intersects.what is the nature of these equations
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Step-by-step explanation:
A system of linear equations ax+by+c=0 and dx+ey+g=0 will have a unique solution if the two lines represented by the equations ax+by+c=0 and dx+ey+g=0 intersect at a point i.e., if the two lines are neither parallel nor coincident.Essentially, the slopes of the two lines should be different.
Writing the equations in slope form we get
y=−
b
1
a
1
x
+
b
1
c
1
y=−
b
2
a
2
x
+
b
2
c
2
For a unique solution, the slopes of the lines should be different.
−
b
1
a
1
=−
b
2
a
2
b
1
a
1
=
b
2
a
2
Hence a
1
b
2
=a
2
b
1
Answered by
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Answer:
This pair of linear equation given by a1x+b1y+c1= 0 and a2x+b2y+c2=0,
- a1/a2 ≠ b1/b2 ≠ c1/c2 if and only if lines are intersect and the nature of the roots unique solution
- a1/a2 = b1/b2 = c1/c2 for this coincident and infinitely many solutions
- a1/a2 = b1/b2 ≠ c1/c2 for this parallel and no solution.
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