if a pair of opposite side of a cyclic quadilateral is equal proove that the diagnols are equal
hardyk09:
it is not necessary that the will be equal
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Let the cyclic quadrilateral be A, B, C and D.
Now join BD and AC.
BD intersect AC at O
Now in triangle ADO
and triangle BCO
angle BDA=angle ACB(angle at same segment are equal)
AD=BC (given)
angle ADO=angle
CBO(angle at same segment are equal)
Therefore, triangle ADO
is congruent to triangle BCO
Now, AO=OB (c .p .c .t)
OC=OD (c .p. c
.t)
AO+OC=BO+OD
Therefore, diagonal AC= diagonal BD
Hence, proved
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