Question

, if a particle experiences location of 20 seconds if it completes if we complete S1 distance in 10 seconds and as to distance in next 10 seconds what is the relationship between S1 and S2​

Answer 1

Answer:

A particle, after starting from rest, experiences constant acceleration for 20 seconds. If it covers a distance of S1 in the first 10 seconds and distance S2 in the next 10 seconds, then what distance does it cover?

The particle starts from rest, so from kinematic equations,

We will use the third kinematic equation here, since the acceleration is same throughout it would work well here.

v2=vo2+2ax

since vo=0 , v2=2ax⟹v22a=x

Now, since acceleration is constant, v=vo+at , t=20s and vo=0 so v=20a

So, 400a22a=x⟹x=200a

Since there's no other information given, that's what you're stuck with.