Question

If a particle having an initial velocity of 20ms-1, moves with a uniform acceleration of 10ms-2, then the distance covered by it when it attains a final velocity of 80 ms-1 is.


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Answer 1

Answer:

Hope it will help you Dost see attachment

Answer 2

Explanation:

Suppose the acceleration is a then using the second equation of motion, s=ut+

$\frac{1}{2} {at}^{2}$

and putting t=2sec and u=10m/s

we get 20=10×2+a×2

or a=0 that is uniform motion.

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