if a particle is thrown upward with a speed of 75m/sec find the distance traveled by particle in 8th second
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Answer:
2.5 m
Explanation:
Method Normal .
Note there is a direction change when ball attains maximum height .
The time taken by ball to get to max height can be found this way :
v = u - gt
0 = 75 - 10t
t = 7.5 seconds.
H = 75*75/20 = 281.25 m
Distance travelled in 8th second = Distance travelled in 8 seconds - Distance travelled in 7 seconds
So, distance travelled in 0.5 s = 5(0.5)^2
= 1.25 m
Distance travelled in 7 seconds =75(7)-5(49)
= 35(15-7) = 8*35 = 280
So , S8 - S7 = (281.25+1.25-280) = 2.5 m
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