Question

If a particle is thrown upward with speed 40 m/s, then the distance travelled by particle in last second of its upward journey is (g is acceleration due to gravity) Choose answer: g 3g g/2 g/4

Answer 1

answer : g/2

explanation : if a particle is thrown upward with speed 40m/s. initial velocity, u = 40m/s

we have to find distance travelled in last second of its upward journey.

time taken to reach highest point, t = u/g

= 40/g

now, using formula,

$S_{nth}=u+\frac{a}{2}(2n-1)$

here, n = t = 40/g , u = 40 , a = -g

Snth = 40 + (-g)/2 (2 × 40/g - 1)

= 40 - 40 + g/2

= g/2

hence, distance travelled by particle in last second of its upward is g/2.

Answer 2

$\huge\bold\purple{Answer:-}$

g/2