Question

If a particle moving in a circular path of radius 5 m and a velocity is expressed as v = 412 m/s, the tangential component of acceleration at t=1s is --- m/s2.​

Answer 1

circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. It can be uniform, with constant angular rate of rotation and constant speed, or non-uniform with a changing rate of rotation.

Answer 2

Answer:

particle moving in circular path with velocity 412 m/s has tangential acceleration 2060 m/s².

Explanation:

for  an object which moves in circular motion  angular acceleration makes two components one is tangential and other is radial component. tangential component is one which is tangential to the direction of motion and perpendicular to radial direction .

tangential acceleration is given as

 $a_{T}= r* a_{r} }$

where $a_{r}$ is radial component

 $a_{r}$ = Δv/Δt

$a_{r}$ = 412/1  

$a_{r}$ =412 m/s²

now

     $a_{T}$ =r× 412  

     $a_{T}$ = 5× 412  

      $a_{T}$ = 2060m/s²