Question

If a particle starting frrom rest is moving with a uniform accletration of 10 ms then the final velocity when it covers a distance of two km is

Answer 1

★ Given :

Initial velocity (u) = 0 m/s = 0 * 18/5 km/h = 0 km/h

Acceleration = 10 m/s² = 10 * 18/5 km/h = 36 km/h

Distance covered (s) = 2 km

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★ To Find :

We have to find the final velocity of particle.

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★ Solution :

We know the third equation of motion

$\Large{\implies{\boxed{\boxed{\sf{v^2 - u^2 = 2as}}}}}$

★ Putting Values ★

$\sf{\dashrightarrow v^2 - (0)^2 = 2 \times 36 \times 2} \\ \\ \sf{\dashrightarrow v^2 = 144} \\ \\ \sf{\dashrightarrow v = \sqrt{144}} \\ \\ \sf{\dashrightarrow v = (\sqrt{12})^2} \\ \\ \sf{\dashrightarrow v = 12} \\ \\ \Large{\implies{\boxed{\boxed{\sf{v = 12 \: kmh^{-1} }}}}}$