larger of two supplementary angles exceeds the smaller by 28 find the angles
Answers
Answered by
1
HERE'S YOUR ANSWER
X + Y = 180
Y=X+28
X+X+28=180
2x+28=180
2x=180-28
2x=152
x=76
from eqn
x+y=180
76+y=180
y=180-76= 104
therefore,
x=76 degree (smaller angle)
y=104 degree (larger angle)
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X + Y = 180
Y=X+28
X+X+28=180
2x+28=180
2x=180-28
2x=152
x=76
from eqn
x+y=180
76+y=180
y=180-76= 104
therefore,
x=76 degree (smaller angle)
y=104 degree (larger angle)
HOPE THIS HELP YOU ❤️
PLEASE MARK AS BRAINLIEST ❤️
karthiknayak11:
please mark as BRAINLIEST ❤️
Answered by
1
Let the larger angle be 'x'
And smaller angle be 'y'
x+y =180° ---------(1)
x - y = 28° ---------(2)
By using elimination method
Add the equations
So,
2x = 208
x = 208/2
[x =104°]
x + y = 180°
y = 180 - 104
[y = 76°]
larger angle is 104° and smaller angle is 76°. ✌✌✌
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