If a particle takes t seconds less and acquires a velocity of 20 metre per second more in falling through the same distance starting from rest on two planets where the acceleration due to gravity are 2g and 8g respectively then
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Answer:
4gt
Explanation:
Given If a particle takes t seconds less and acquires a velocity of v metre per second more in falling through the same distance starting from rest on two planets where the acceleration due to gravity are 2g and 8g respectively then
We know that
v/t = v1 – v2 /t2 – t1
= √2a1s - √2a2s / √2s/a2 - √2s/a1
v = (√a1 a2)t
So v = √2g 8g t
v = √16 g^2t
v = 4gt
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