If a quadratic equation whose one root is 1+root 2 and the sum of its roots is 2 is
Answers
here we have to find the quadratic equation whose one root is 1+ √2 and the sum of its roots is 2.
let the other root of the equation be x.
➡ 1 + √2 + x = 2
➡ x = 2 - 1 - √2
➡ x = 1 - √2
another root of the quadratic equation is 1 - √2
therefore product of the roots = (1 + √2)(1 - √2)
using identity (a + b)(a - b) = a² - b²
= (1)² - (√2)²
= 1 - 2
= -1
now we know that,
sum of roots = -b/a
product of roots = c/a
- 2 = -b/a
➡ b/a = -2
- -1 = c/a
therefore a = 1, b = -2 and c = -1
standard form of quadratic equation = ax² + bx + c
hence, the quadratic equation is =
x² - 2x - c
First root :- 1+√2
let other root be x
So,
» x+1+√2 = 2
» x = 2-1-√2
» x = 1- √2
☞ So, other root is 1-√2
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Product of roots :-
» (1+√2)(1-√2)
» (1)² - (√2)² [ By a² - b² = (a+b)(a-b)]
» 1-2
» -1
We know :-
sum of roots = -b/a
products of roots = c/a
» 2 = -b/a
» b/a = -2
» c/a = -1
a=1, b= -2 , c= -1
_________________________
So, general form of equation is
ax² + bx + c
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A.T.Q,
x² - 2x - c