Question

If a perfect cube is divided by 9, there are only 3 possible remainders. Give an example for each.
With working

Answer 1

Answer:

1 ,8,0

Step-by-step explanation:

When 3^3 =27 is devided by 9 it leaves the reamainder 0

When 4^3 =64 is devided by 9 it leaves reaminder 1

When 5^3 =125 is devided by 9 it leaves the remainder 8

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