If a person goes to a height equal to radius of earth from its surface, what would be his weight relative to that on the earth?
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Answered by
36
Let me help you with this question.
We know that,
W = mg
W = m x GM / R₍e₎² (∵ g = GM/R₍e₎² )
m = W.R₍e₎² / GM ............ (1)
Now, if a person goes to a height equal to radius of earth 'R' from its surface, then,
g' = GM / (R₍e₎ + h)² .......... (2)
Now, weight at height 'R' is given as
W' = mg'
W' = [W.R₍e₎² / GM ] x [GM / (R₍e₎ + h)²] ( Using (1) and (2) )
W' = W x [ R₍e₎² / (R₍e₎ + h)² ]
This is the required answer.
Hopefully it helps.
Thanks.
We know that,
W = mg
W = m x GM / R₍e₎² (∵ g = GM/R₍e₎² )
m = W.R₍e₎² / GM ............ (1)
Now, if a person goes to a height equal to radius of earth 'R' from its surface, then,
g' = GM / (R₍e₎ + h)² .......... (2)
Now, weight at height 'R' is given as
W' = mg'
W' = [W.R₍e₎² / GM ] x [GM / (R₍e₎ + h)²] ( Using (1) and (2) )
W' = W x [ R₍e₎² / (R₍e₎ + h)² ]
This is the required answer.
Hopefully it helps.
Thanks.
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