If a person travels at the speed of 30 km per hour then he reaches his destination 10 minutes late while travelling at a speed of 42 kilometre per hour he reaches his destination 10 minutes before the distance travelled by the person is
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Answer: Let the time taken when he reaches on time be T and distance of school be D
T + 1/6 = D/30 ............................... (1)
T - 1/6 = D/40 .................................(2)
Subtracting (2) from (1) and solving further we get
∴ D= 35 KM
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