. If a piece of stone has attained a velocity of 88.2 m/sec after falling for 8 seconds, what
was its initial velocity?
Answers
Answered by
3
Answer:
the stone's final speed just before hitting the ground is: v = √(2 × 9.81 × 90) m/s = √(1765.8) m/s = 42.0 m/s.
Answered by
1
Answer: Acceleration- change of velocity by time taken
Explanation:
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