Question

If a planet existed whose mass was twice that of the earth and whose radius is 3 times greater. What will be weigh on its surface of object of mass 10 kg.

Answer 1

$hey....$

the value of g on earth=

$\frac{gm}{ {r}^{2} }$

if the value of radius become 3times and mass becomes increase twice

so,

g'=

$\frac{g \times 2m}{ {(3r)}^{2} }$

$= \frac{2}{9} \times \frac{gm}{ {(r)}^{2} } \\ \frac{2}{9} \times g$

so, g'=2/9 g

weight of object oo that planet = mg'

$w = 10 \times \frac{2}{9} \times g$

$w = 10 \times \frac{2}{9} \times 9.8 \\ w = 21.77kg \: or \: \frac{20}{9} g$

Answer 2

Answer:47.40 kg according to me

Explanation: